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2116262141353 = 14083150270691
BaseRepresentation
bin11110110010111011000…
…011011001110110101001
321111022102221120120100101
4132302323003121312221
5234133101102010403
64300110350105401
7305615643254263
oct36627303316651
97438387516311
102116262141353
11746557898428
122a218baab261
13124741230b59
14745db5dcb33
153a0aec3e71d
hex1ecbb0d9da9

2116262141353 has 4 divisors (see below), whose sum is σ = 2116412426128. Its totient is φ = 2116111856580.

The previous prime is 2116262141347. The next prime is 2116262141363. The reversal of 2116262141353 is 3531412626112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2116262141353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2116262141363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75121263 + ... + 75149428.

It is an arithmetic number, because the mean of its divisors is an integer number (529103106532).

Almost surely, 22116262141353 is an apocalyptic number.

It is an amenable number.

2116262141353 is a deficient number, since it is larger than the sum of its proper divisors (150284775).

2116262141353 is a wasteful number, since it uses less digits than its factorization.

2116262141353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 150284774.

The product of its digits is 51840, while the sum is 37.

Adding to 2116262141353 its reverse (3531412626112), we get a palindrome (5647674767465).

The spelling of 2116262141353 in words is "two trillion, one hundred sixteen billion, two hundred sixty-two million, one hundred forty-one thousand, three hundred fifty-three".

Divisors: 1 14083 150270691 2116262141353