Base | Representation |
---|---|
bin | 1100010100110110011… |
… | …0110100101100010001 |
3 | 202020120121011220202101 |
4 | 3011031212310230101 |
5 | 11432133341423213 |
6 | 241140141320401 |
7 | 21204332242534 |
oct | 3051546645421 |
9 | 666517156671 |
10 | 211755420433 |
11 | 818944615a7 |
12 | 35058566101 |
13 | 16c788bb55b |
14 | a36b434a1b |
15 | 57954d1bdd |
hex | 314d9b4b11 |
211755420433 has 8 divisors (see below), whose sum is σ = 212198025600. Its totient is φ = 211312920528.
The previous prime is 211755420397. The next prime is 211755420439. The reversal of 211755420433 is 334024557112.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 211755420433 - 221 = 211753323281 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 211755420392 and 211755420401.
It is not an unprimeable number, because it can be changed into a prime (211755420439) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4986910 + ... + 5029192.
It is an arithmetic number, because the mean of its divisors is an integer number (26524753200).
Almost surely, 2211755420433 is an apocalyptic number.
It is an amenable number.
211755420433 is a deficient number, since it is larger than the sum of its proper divisors (442605167).
211755420433 is an equidigital number, since it uses as much as digits as its factorization.
211755420433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52631.
The product of its (nonzero) digits is 100800, while the sum is 37.
Adding to 211755420433 its reverse (334024557112), we get a palindrome (545779977545).
The spelling of 211755420433 in words is "two hundred eleven billion, seven hundred fifty-five million, four hundred twenty thousand, four hundred thirty-three".
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