Base | Representation |
---|---|
bin | 11110110101010110010… |
… | …101100110011110100011 |
3 | 21111120011111210102002111 |
4 | 132311112111212132203 |
5 | 234203420022131011 |
6 | 4301221053300151 |
7 | 306040336364515 |
oct | 36652625463643 |
9 | 7446144712074 |
10 | 2118867380131 |
11 | 747674440927 |
12 | 2a2798494657 |
13 | 124a67bb9468 |
14 | 747a7605bb5 |
15 | 3a1b3807121 |
hex | 1ed565667a3 |
2118867380131 has 2 divisors, whose sum is σ = 2118867380132. Its totient is φ = 2118867380130.
The previous prime is 2118867379921. The next prime is 2118867380153. The reversal of 2118867380131 is 1310837688112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2118867380131 - 211 = 2118867378083 is a prime.
It is a super-2 number, since 2×21188673801312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2118867380191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1059433690065 + 1059433690066.
It is an arithmetic number, because the mean of its divisors is an integer number (1059433690066).
Almost surely, 22118867380131 is an apocalyptic number.
2118867380131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2118867380131 is an equidigital number, since it uses as much as digits as its factorization.
2118867380131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 387072, while the sum is 49.
The spelling of 2118867380131 in words is "two trillion, one hundred eighteen billion, eight hundred sixty-seven million, three hundred eighty thousand, one hundred thirty-one".
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