Base | Representation |
---|---|
bin | 11110110101101011010… |
… | …100010110110101111011 |
3 | 21111121002001010121221101 |
4 | 132311223110112311323 |
5 | 234210130130003413 |
6 | 4301320025552231 |
7 | 306052142322160 |
oct | 36655324266573 |
9 | 7447061117841 |
10 | 2119219375483 |
11 | 7478350a9181 |
12 | 2a2876345677 |
13 | 124ac2ac0932 |
14 | 747dc272067 |
15 | 3a1d4686edd |
hex | 1ed6b516d7b |
2119219375483 has 4 divisors (see below), whose sum is σ = 2421965000560. Its totient is φ = 1816473750408.
The previous prime is 2119219375453. The next prime is 2119219375517. The reversal of 2119219375483 is 3845739129112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2119219375483 - 25 = 2119219375451 is a prime.
It is a super-2 number, since 2×21192193754832 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2119219375453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151372812528 + ... + 151372812541.
It is an arithmetic number, because the mean of its divisors is an integer number (605491250140).
Almost surely, 22119219375483 is an apocalyptic number.
2119219375483 is a deficient number, since it is larger than the sum of its proper divisors (302745625077).
2119219375483 is an equidigital number, since it uses as much as digits as its factorization.
2119219375483 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 302745625076.
The product of its digits is 3265920, while the sum is 55.
The spelling of 2119219375483 in words is "two trillion, one hundred nineteen billion, two hundred nineteen million, three hundred seventy-five thousand, four hundred eighty-three".
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