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2120011411153 is a prime number
BaseRepresentation
bin11110110110011010100…
…001101110111011010001
321111200010020111012121211
4132312122201232323101
5234213240410124103
64301530402020121
7306110600445106
oct36663241567321
97450106435554
102120011411153
1174810119a309
122a2a57647641
13124bbac156ac
1474875526aad
153a22de8936d
hex1ed9a86eed1

2120011411153 has 2 divisors, whose sum is σ = 2120011411154. Its totient is φ = 2120011411152.

The previous prime is 2120011411073. The next prime is 2120011411171. The reversal of 2120011411153 is 3511141100212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2010590710209 + 109420700944 = 1417953^2 + 330788^2 .

It is a cyclic number.

It is not a de Polignac number, because 2120011411153 - 213 = 2120011402961 is a prime.

It is not a weakly prime, because it can be changed into another prime (2120011481153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060005705576 + 1060005705577.

It is an arithmetic number, because the mean of its divisors is an integer number (1060005705577).

Almost surely, 22120011411153 is an apocalyptic number.

It is an amenable number.

2120011411153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2120011411153 is an equidigital number, since it uses as much as digits as its factorization.

2120011411153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 2120011411153 its reverse (3511141100212), we get a palindrome (5631152511365).

The spelling of 2120011411153 in words is "two trillion, one hundred twenty billion, eleven million, four hundred eleven thousand, one hundred fifty-three".