Base | Representation |
---|---|
bin | 1100010101110001001… |
… | …1101010000101010011 |
3 | 202021012210021020001211 |
4 | 3011130103222011103 |
5 | 11433140011220413 |
6 | 241220431440551 |
7 | 21213415505332 |
oct | 3053423520523 |
9 | 667183236054 |
10 | 212002054483 |
11 | 81a006a639a |
12 | 35107086157 |
13 | 16cb7a22b6b |
14 | a3920b5d19 |
15 | 57abe9d83d |
hex | 315c4ea153 |
212002054483 has 2 divisors, whose sum is σ = 212002054484. Its totient is φ = 212002054482.
The previous prime is 212002054471. The next prime is 212002054487. The reversal of 212002054483 is 384450200212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212002054483 is a prime.
It is a super-3 number, since 3×2120020544833 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (212002054487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106001027241 + 106001027242.
It is an arithmetic number, because the mean of its divisors is an integer number (106001027242).
Almost surely, 2212002054483 is an apocalyptic number.
212002054483 is a deficient number, since it is larger than the sum of its proper divisors (1).
212002054483 is an equidigital number, since it uses as much as digits as its factorization.
212002054483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15360, while the sum is 31.
Adding to 212002054483 its reverse (384450200212), we get a palindrome (596452254695).
The spelling of 212002054483 in words is "two hundred twelve billion, two million, fifty-four thousand, four hundred eighty-three".
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