Base | Representation |
---|---|
bin | 1100010101110001001… |
… | …1111000011001100001 |
3 | 202021012210101012111121 |
4 | 3011130103320121201 |
5 | 11433140020104441 |
6 | 241220433012241 |
7 | 21213416141311 |
oct | 3053423703141 |
9 | 667183335447 |
10 | 212002113121 |
11 | 81a00736457 |
12 | 351070b4081 |
13 | 16cb7a43766 |
14 | a3920cd441 |
15 | 57abeb0dd1 |
hex | 315c4f8661 |
212002113121 has 2 divisors, whose sum is σ = 212002113122. Its totient is φ = 212002113120.
The previous prime is 212002113091. The next prime is 212002113157. The reversal of 212002113121 is 121311200212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 180039824721 + 31962288400 = 424311^2 + 178780^2 .
It is a cyclic number.
It is not a de Polignac number, because 212002113121 - 219 = 212001588833 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 212002113095 and 212002113104.
It is not a weakly prime, because it can be changed into another prime (212002113161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106001056560 + 106001056561.
It is an arithmetic number, because the mean of its divisors is an integer number (106001056561).
Almost surely, 2212002113121 is an apocalyptic number.
It is an amenable number.
212002113121 is a deficient number, since it is larger than the sum of its proper divisors (1).
212002113121 is an equidigital number, since it uses as much as digits as its factorization.
212002113121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 212002113121 its reverse (121311200212), we get a palindrome (333313313333).
The spelling of 212002113121 in words is "two hundred twelve billion, two million, one hundred thirteen thousand, one hundred twenty-one".
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