Base | Representation |
---|---|
bin | 110000001101001001101100… |
… | …110110111010110011011001 |
3 | 1000210122221212120020110111112 |
4 | 300031021230312322303121 |
5 | 210242032441003013423 |
6 | 2030524014513110105 |
7 | 62441134330045241 |
oct | 6015115466726331 |
9 | 1023587776213445 |
10 | 212010002001113 |
11 | 61609a34049678 |
12 | 1b940b60858335 |
13 | 913b5c3bb9a04 |
14 | 3a4d4a5b26b21 |
15 | 1979d00115a78 |
hex | c0d26cdbacd9 |
212010002001113 has 2 divisors, whose sum is σ = 212010002001114. Its totient is φ = 212010002001112.
The previous prime is 212010002001101. The next prime is 212010002001197. The reversal of 212010002001113 is 311100200010212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 204803204036809 + 7206797964304 = 14310947^2 + 2684548^2 .
It is a cyclic number.
It is not a de Polignac number, because 212010002001113 - 24 = 212010002001097 is a prime.
It is not a weakly prime, because it can be changed into another prime (212010002001013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106005001000556 + 106005001000557.
It is an arithmetic number, because the mean of its divisors is an integer number (106005001000557).
Almost surely, 2212010002001113 is an apocalyptic number.
It is an amenable number.
212010002001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
212010002001113 is an equidigital number, since it uses as much as digits as its factorization.
212010002001113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 212010002001113 its reverse (311100200010212), we get a palindrome (523110202011325).
The spelling of 212010002001113 in words is "two hundred twelve trillion, ten billion, two million, one thousand, one hundred thirteen".
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