Base | Representation |
---|---|
bin | 110000001101001011110000… |
… | …100001101000100101111011 |
3 | 1000210200011120111212221112001 |
4 | 300031023300201220211323 |
5 | 210242102002004422021 |
6 | 2030525022024001431 |
7 | 62441243142253132 |
oct | 6015136041504573 |
9 | 1023604514787461 |
10 | 212012211014011 |
11 | 6160a967a74771 |
12 | 1b941478600277 |
13 | 913b886755835 |
14 | 3a4d63526c919 |
15 | 1979dce013091 |
hex | c0d2f086897b |
212012211014011 has 2 divisors, whose sum is σ = 212012211014012. Its totient is φ = 212012211014010.
The previous prime is 212012211013949. The next prime is 212012211014039. The reversal of 212012211014011 is 110410112210212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212012211014011 - 223 = 212012202625403 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 212012211014011.
It is not a weakly prime, because it can be changed into another prime (212012211014311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006105507005 + 106006105507006.
It is an arithmetic number, because the mean of its divisors is an integer number (106006105507006).
Almost surely, 2212012211014011 is an apocalyptic number.
212012211014011 is a deficient number, since it is larger than the sum of its proper divisors (1).
212012211014011 is an equidigital number, since it uses as much as digits as its factorization.
212012211014011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 212012211014011 its reverse (110410112210212), we get a palindrome (322422323224223).
The spelling of 212012211014011 in words is "two hundred twelve trillion, twelve billion, two hundred eleven million, fourteen thousand, eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •