Base | Representation |
---|---|
bin | 1001101001000010010111… |
… | …10111100010001111000001 |
3 | 2210001211002021022100121021 |
4 | 10310201023313202033001 |
5 | 10234330110221004101 |
6 | 113031413344225441 |
7 | 4315511164444462 |
oct | 464411367421701 |
9 | 83054067270537 |
10 | 21201231422401 |
11 | 6834434471a98 |
12 | 2464b3560b281 |
13 | baa362a45444 |
14 | 534206134d69 |
15 | 26b75cc175a1 |
hex | 13484bde23c1 |
21201231422401 has 2 divisors, whose sum is σ = 21201231422402. Its totient is φ = 21201231422400.
The previous prime is 21201231422387. The next prime is 21201231422419. The reversal of 21201231422401 is 10422413210212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20959045391025 + 242186031376 = 4578105^2 + 492124^2 .
It is a cyclic number.
It is not a de Polignac number, because 21201231422401 - 215 = 21201231389633 is a prime.
It is not a weakly prime, because it can be changed into another prime (21201231422801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10600615711200 + 10600615711201.
It is an arithmetic number, because the mean of its divisors is an integer number (10600615711201).
Almost surely, 221201231422401 is an apocalyptic number.
It is an amenable number.
21201231422401 is a deficient number, since it is larger than the sum of its proper divisors (1).
21201231422401 is an equidigital number, since it uses as much as digits as its factorization.
21201231422401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 21201231422401 its reverse (10422413210212), we get a palindrome (31623644632613).
The spelling of 21201231422401 in words is "twenty-one trillion, two hundred one billion, two hundred thirty-one million, four hundred twenty-two thousand, four hundred one".
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