Base | Representation |
---|---|
bin | 11110110110100001001… |
… | …101001000010010111001 |
3 | 21111200102001022101210020 |
4 | 132312201031020102321 |
5 | 234214003100404203 |
6 | 4301545443241053 |
7 | 306113430662433 |
oct | 36664115102271 |
9 | 7450361271706 |
10 | 2120123450553 |
11 | 748159464159 |
12 | 2a2a89079189 |
13 | 124c081b30b4 |
14 | 7488636d653 |
15 | 3a238c1b153 |
hex | 1eda13484b9 |
2120123450553 has 4 divisors (see below), whose sum is σ = 2826831267408. Its totient is φ = 1413415633700.
The previous prime is 2120123450551. The next prime is 2120123450569. The reversal of 2120123450553 is 3550543210212.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2120123450553 - 21 = 2120123450551 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2120123450551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353353908423 + ... + 353353908428.
It is an arithmetic number, because the mean of its divisors is an integer number (706707816852).
Almost surely, 22120123450553 is an apocalyptic number.
It is an amenable number.
2120123450553 is a deficient number, since it is larger than the sum of its proper divisors (706707816855).
2120123450553 is an equidigital number, since it uses as much as digits as its factorization.
2120123450553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 706707816854.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 2120123450553 its reverse (3550543210212), we get a palindrome (5670666660765).
The spelling of 2120123450553 in words is "two trillion, one hundred twenty billion, one hundred twenty-three million, four hundred fifty thousand, five hundred fifty-three".
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