Base | Representation |
---|---|
bin | 1100010101110011111… |
… | …0001011011100110011 |
3 | 202021020120020112111022 |
4 | 3011130332023130303 |
5 | 11433200334414303 |
6 | 241221510410055 |
7 | 21213612322136 |
oct | 3053476133463 |
9 | 667216215438 |
10 | 212013201203 |
11 | 81a06a1a061 |
12 | 3510a96092b |
13 | 16cba12665b |
14 | a39377821d |
15 | 57ace51438 |
hex | 315cf8b733 |
212013201203 has 16 divisors (see below), whose sum is σ = 229506815520. Its totient is φ = 195167460096.
The previous prime is 212013201181. The next prime is 212013201217. The reversal of 212013201203 is 302102310212.
It is not a de Polignac number, because 212013201203 - 234 = 194833332019 is a prime.
It is not an unprimeable number, because it can be changed into a prime (212013201223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 332975 + ... + 731367.
It is an arithmetic number, because the mean of its divisors is an integer number (14344175970).
Almost surely, 2212013201203 is an apocalyptic number.
212013201203 is a deficient number, since it is larger than the sum of its proper divisors (17493614317).
212013201203 is a wasteful number, since it uses less digits than its factorization.
212013201203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399206.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 212013201203 its reverse (302102310212), we get a palindrome (514115511415).
The spelling of 212013201203 in words is "two hundred twelve billion, thirteen million, two hundred one thousand, two hundred three".
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