Base | Representation |
---|---|
bin | 1100010101110011111… |
… | …0101001001110001011 |
3 | 202021020120110201202202 |
4 | 3011130332221032023 |
5 | 11433200402320042 |
6 | 241221513150415 |
7 | 21213613340513 |
oct | 3053476511613 |
9 | 667216421682 |
10 | 212013323147 |
11 | 81a06aa273a |
12 | 3510a9bb40b |
13 | 16cba16a002 |
14 | a3937aa843 |
15 | 57ace77632 |
hex | 315cfa938b |
212013323147 has 2 divisors, whose sum is σ = 212013323148. Its totient is φ = 212013323146.
The previous prime is 212013323117. The next prime is 212013323233. The reversal of 212013323147 is 741323310212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212013323147 - 216 = 212013257611 is a prime.
It is not a weakly prime, because it can be changed into another prime (212013323117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106006661573 + 106006661574.
It is an arithmetic number, because the mean of its divisors is an integer number (106006661574).
Almost surely, 2212013323147 is an apocalyptic number.
212013323147 is a deficient number, since it is larger than the sum of its proper divisors (1).
212013323147 is an equidigital number, since it uses as much as digits as its factorization.
212013323147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 212013323147 its reverse (741323310212), we get a palindrome (953336633359).
The spelling of 212013323147 in words is "two hundred twelve billion, thirteen million, three hundred twenty-three thousand, one hundred forty-seven".
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