Base | Representation |
---|---|
bin | 1001101001000011110011… |
… | …01011110110101000000011 |
3 | 2210001220001211201211200021 |
4 | 10310201321223312220003 |
5 | 10234333144012042011 |
6 | 113032021524034311 |
7 | 4315536220264426 |
oct | 464417153665003 |
9 | 83056054654607 |
10 | 21202000112131 |
11 | 6834799367a63 |
12 | 246510ab32997 |
13 | baa456084b37 |
14 | 53427a26d9bd |
15 | 26b7a5457471 |
hex | 134879af6a03 |
21202000112131 has 2 divisors, whose sum is σ = 21202000112132. Its totient is φ = 21202000112130.
The previous prime is 21202000112101. The next prime is 21202000112141. The reversal of 21202000112131 is 13121100020212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21202000112131 - 219 = 21201999587843 is a prime.
It is a super-2 number, since 2×212020001121312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21202000112101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10601000056065 + 10601000056066.
It is an arithmetic number, because the mean of its divisors is an integer number (10601000056066).
Almost surely, 221202000112131 is an apocalyptic number.
21202000112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21202000112131 is an equidigital number, since it uses as much as digits as its factorization.
21202000112131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 21202000112131 its reverse (13121100020212), we get a palindrome (34323100132343).
The spelling of 21202000112131 in words is "twenty-one trillion, two hundred two billion, one hundred twelve thousand, one hundred thirty-one".
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