Base | Representation |
---|---|
bin | 1100010101110101100… |
… | …0001010000001101001 |
3 | 202021021001001111221012 |
4 | 3011131120022001221 |
5 | 11433204110323423 |
6 | 241222312353305 |
7 | 21214024234121 |
oct | 3053530120151 |
9 | 667231044835 |
10 | 212020011113 |
11 | 81a0a850489 |
12 | 351110a5835 |
13 | 16cbb66c1a1 |
14 | a39462bc81 |
15 | 57ad849078 |
hex | 315d60a069 |
212020011113 has 2 divisors, whose sum is σ = 212020011114. Its totient is φ = 212020011112.
The previous prime is 212020011101. The next prime is 212020011173. The reversal of 212020011113 is 311110020212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 209849196649 + 2170814464 = 458093^2 + 46592^2 .
It is a cyclic number.
It is not a de Polignac number, because 212020011113 - 24 = 212020011097 is a prime.
It is a super-2 number, since 2×2120200111132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (212020011173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106010005556 + 106010005557.
It is an arithmetic number, because the mean of its divisors is an integer number (106010005557).
Almost surely, 2212020011113 is an apocalyptic number.
It is an amenable number.
212020011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
212020011113 is an equidigital number, since it uses as much as digits as its factorization.
212020011113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 212020011113 its reverse (311110020212), we get a palindrome (523130031325).
Subtracting 212020011113 from its reverse (311110020212), we obtain a palindrome (99090009099).
The spelling of 212020011113 in words is "two hundred twelve billion, twenty million, eleven thousand, one hundred thirteen".
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