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21202102113 = 37067367371
BaseRepresentation
bin10011101111101111…
…100110011101100001
32000201121111101100020
4103233233212131201
5321410214231423
613423510344053
71350256615533
oct235757463541
960647441306
1021202102113
118aa0041145
12413865b029
131ccb756b6a
141051c01853
1584156e4e3
hex4efbe6761

21202102113 has 4 divisors (see below), whose sum is σ = 28269469488. Its totient is φ = 14134734740.

The previous prime is 21202102111. The next prime is 21202102153. The reversal of 21202102113 is 31120120212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21202102113 - 21 = 21202102111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21202102092 and 21202102101.

It is not an unprimeable number, because it can be changed into a prime (21202102111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3533683683 + ... + 3533683688.

It is an arithmetic number, because the mean of its divisors is an integer number (7067367372).

Almost surely, 221202102113 is an apocalyptic number.

It is an amenable number.

21202102113 is a deficient number, since it is larger than the sum of its proper divisors (7067367375).

21202102113 is an equidigital number, since it uses as much as digits as its factorization.

21202102113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7067367374.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 21202102113 its reverse (31120120212), we get a palindrome (52322222325).

The spelling of 21202102113 in words is "twenty-one billion, two hundred two million, one hundred two thousand, one hundred thirteen".

Divisors: 1 3 7067367371 21202102113