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2120234115 = 35920915349
BaseRepresentation
bin111111001100000…
…0011010010000011
312110202121001102110
41332120003102003
513320234442430
6550215550403
7103353456366
oct17630032203
95422531373
102120234115
119988a92aa
124b208b403
1327a3539cc
141618360dd
15c62127b0
hex7e603483

2120234115 has 16 divisors (see below), whose sum is σ = 3392964000. Its totient is φ = 1130595072.

The previous prime is 2120234113. The next prime is 2120234159. The reversal of 2120234115 is 5114320212.

It is a Cunningham number, because it is equal to 460462-1.

It is not a de Polignac number, because 2120234115 - 21 = 2120234113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2120234091 and 2120234100.

It is not an unprimeable number, because it can be changed into a prime (2120234113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 130461 + ... + 145809.

It is an arithmetic number, because the mean of its divisors is an integer number (212060250).

Almost surely, 22120234115 is an apocalyptic number.

2120234115 is a deficient number, since it is larger than the sum of its proper divisors (1272729885).

2120234115 is a wasteful number, since it uses less digits than its factorization.

2120234115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24566.

The product of its (nonzero) digits is 480, while the sum is 21.

The square root of 2120234115 is about 46045.9999891413. Note that the first 4 decimals coincide. The cubic root of 2120234115 is about 1284.6789439500.

Adding to 2120234115 its reverse (5114320212), we get a palindrome (7234554327).

The spelling of 2120234115 in words is "two billion, one hundred twenty million, two hundred thirty-four thousand, one hundred fifteen".

Divisors: 1 3 5 15 9209 15349 27627 46045 46047 76745 138135 230235 141348941 424046823 706744705 2120234115