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212034444131 = 832554631857
BaseRepresentation
bin1100010101111000111…
…1001101101101100011
3202021022001012210022102
43011132033031231203
511433221304203011
6241223550001015
721214261015646
oct3053617155543
9667261183272
10212034444131
1181a17a091a4
1235115aa616b
1316cc1653733
14a396507a5d
1557aec4a73b
hex315e3cdb63

212034444131 has 4 divisors (see below), whose sum is σ = 214589076072. Its totient is φ = 209479812192.

The previous prime is 212034444119. The next prime is 212034444151. The reversal of 212034444131 is 131444430212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 212034444131 - 26 = 212034444067 is a prime.

It is a super-2 number, since 2×2120344441312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212034444094 and 212034444103.

It is not an unprimeable number, because it can be changed into a prime (212034444151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1277315846 + ... + 1277316011.

It is an arithmetic number, because the mean of its divisors is an integer number (53647269018).

Almost surely, 2212034444131 is an apocalyptic number.

212034444131 is a deficient number, since it is larger than the sum of its proper divisors (2554631941).

212034444131 is an equidigital number, since it uses as much as digits as its factorization.

212034444131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2554631940.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 212034444131 its reverse (131444430212), we get a palindrome (343478874343).

The spelling of 212034444131 in words is "two hundred twelve billion, thirty-four million, four hundred forty-four thousand, one hundred thirty-one".

Divisors: 1 83 2554631857 212034444131