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212054141401 is a prime number
BaseRepresentation
bin1100010101111101101…
…0010110100111011001
3202021100102021111212221
43011133122112213121
511433241330011101
6241225532104041
721214620314254
oct3053732264731
9667312244787
10212054141401
1181a28042033
1235120605021
1316cc575c11b
14a398d9409b
1557b183baa1
hex315f6969d9

212054141401 has 2 divisors, whose sum is σ = 212054141402. Its totient is φ = 212054141400.

The previous prime is 212054141329. The next prime is 212054141489. The reversal of 212054141401 is 104141450212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 212046435225 + 7706176 = 460485^2 + 2776^2 .

It is a cyclic number.

It is not a de Polignac number, because 212054141401 - 237 = 74615187929 is a prime.

It is a super-4 number, since 4×2120541414014 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is not a weakly prime, because it can be changed into another prime (212054141501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106027070700 + 106027070701.

It is an arithmetic number, because the mean of its divisors is an integer number (106027070701).

Almost surely, 2212054141401 is an apocalyptic number.

It is an amenable number.

212054141401 is a deficient number, since it is larger than the sum of its proper divisors (1).

212054141401 is an equidigital number, since it uses as much as digits as its factorization.

212054141401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1280, while the sum is 25.

Adding to 212054141401 its reverse (104141450212), we get a palindrome (316195591613).

The spelling of 212054141401 in words is "two hundred twelve billion, fifty-four million, one hundred forty-one thousand, four hundred one".