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212071492889 is a prime number
BaseRepresentation
bin1100010110000001110…
…0100010110100011001
3202021101121221001122122
43011200130202310121
511433310300233024
6241231352031025
721215220642554
oct3054034426431
9667347831578
10212071492889
1181a36913503
1235126392475
1316cc9225b89
14a39b3cd69b
1557b3117d5e
hex3160722d19

212071492889 has 2 divisors, whose sum is σ = 212071492890. Its totient is φ = 212071492888.

The previous prime is 212071492817. The next prime is 212071492949. The reversal of 212071492889 is 988294170212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 203123278864 + 8948214025 = 450692^2 + 94595^2 .

It is a cyclic number.

It is not a de Polignac number, because 212071492889 - 224 = 212054715673 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 212071492889.

It is not a weakly prime, because it can be changed into another prime (212071092889) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106035746444 + 106035746445.

It is an arithmetic number, because the mean of its divisors is an integer number (106035746445).

Almost surely, 2212071492889 is an apocalyptic number.

It is an amenable number.

212071492889 is a deficient number, since it is larger than the sum of its proper divisors (1).

212071492889 is an equidigital number, since it uses as much as digits as its factorization.

212071492889 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1161216, while the sum is 53.

The spelling of 212071492889 in words is "two hundred twelve billion, seventy-one million, four hundred ninety-two thousand, eight hundred eighty-nine".