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21210100000003 = 201110547041273
BaseRepresentation
bin1001101001010010111000…
…11110011110010100000011
32210002122222100002202222101
410310221130132132110003
510240001241100000003
6113035441352451231
74316244023222035
oct464513436362403
983078870082871
1021210100000003
11683817555a672
1224667ab6a9b17
13bab1471cc6b5
14534807cd9c55
1526bacb5d411d
hex134a5c79e503

21210100000003 has 4 divisors (see below), whose sum is σ = 21220647043288. Its totient is φ = 21199552956720.

The previous prime is 21210099999971. The next prime is 21210100000093. The reversal of 21210100000003 is 30000000101212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21210100000003 - 25 = 21210099999971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21210100000093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5273518626 + ... + 5273522647.

It is an arithmetic number, because the mean of its divisors is an integer number (5305161760822).

Almost surely, 221210100000003 is an apocalyptic number.

21210100000003 is a deficient number, since it is larger than the sum of its proper divisors (10547043285).

21210100000003 is a wasteful number, since it uses less digits than its factorization.

21210100000003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10547043284.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 21210100000003 its reverse (30000000101212), we get a palindrome (51210100101215).

The spelling of 21210100000003 in words is "twenty-one trillion, two hundred ten billion, one hundred million, three", and thus it is an aban number.

Divisors: 1 2011 10547041273 21210100000003