Search a number
-
+
2121011979433 is a prime number
BaseRepresentation
bin11110110111010110001…
…010100110010010101001
321111202200222020100021021
4132313112022212102221
5234222313031320213
64302213543412441
7306144440233564
oct36672612462251
97452628210237
102121011979433
11748574a71046
122a3096754121
1312501a2c1429
147492c3814db
153a28bc2dd8d
hex1edd62a64a9

2121011979433 has 2 divisors, whose sum is σ = 2121011979434. Its totient is φ = 2121011979432.

The previous prime is 2121011979409. The next prime is 2121011979547. The reversal of 2121011979433 is 3349791101212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1987287922944 + 133724056489 = 1409712^2 + 365683^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2121011979433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2121011979433.

It is not a weakly prime, because it can be changed into another prime (2121011979833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060505989716 + 1060505989717.

It is an arithmetic number, because the mean of its divisors is an integer number (1060505989717).

Almost surely, 22121011979433 is an apocalyptic number.

It is an amenable number.

2121011979433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2121011979433 is an equidigital number, since it uses as much as digits as its factorization.

2121011979433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 43.

The spelling of 2121011979433 in words is "two trillion, one hundred twenty-one billion, eleven million, nine hundred seventy-nine thousand, four hundred thirty-three".