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212102144092147 is a prime number
BaseRepresentation
bin110000001110011111100000…
…111101000110011111110011
31000210222202201002211200002211
4300032133200331012133303
5210300040142341422042
62031034214013552551
762450605566643201
oct6016374075063763
91023882632750084
10212102144092147
1161645017937431
121b956996aa5757
1391471b974637a
143a53b2730a071
15197c3e4571017
hexc0e7e0f467f3

212102144092147 has 2 divisors, whose sum is σ = 212102144092148. Its totient is φ = 212102144092146.

The previous prime is 212102144092141. The next prime is 212102144092261. The reversal of 212102144092147 is 741290441201212.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 212102144092147 - 235 = 212067784353779 is a prime.

It is a super-4 number, since 4×2121021440921474 (a number of 58 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (212102144092141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106051072046073 + 106051072046074.

It is an arithmetic number, because the mean of its divisors is an integer number (106051072046074).

Almost surely, 2212102144092147 is an apocalyptic number.

212102144092147 is a deficient number, since it is larger than the sum of its proper divisors (1).

212102144092147 is an equidigital number, since it uses as much as digits as its factorization.

212102144092147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64512, while the sum is 40.

Adding to 212102144092147 its reverse (741290441201212), we get a palindrome (953392585293359).

The spelling of 212102144092147 in words is "two hundred twelve trillion, one hundred two billion, one hundred forty-four million, ninety-two thousand, one hundred forty-seven".