Search a number
-
+
2121040113 = 31674233613
BaseRepresentation
bin111111001101100…
…1000000011110001
312110211010000001020
41332123020003301
513320441240423
6550245130053
7103363354263
oct17633100361
95424100036
102121040113
119992a9915
124b23b9929
1327a57682a
141619a5b33
15c63214e3
hex7e6c80f1

2121040113 has 8 divisors (see below), whose sum is σ = 2844988608. Its totient is φ = 1405559184.

The previous prime is 2121040099. The next prime is 2121040123. The reversal of 2121040113 is 3110401212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2121040113 - 26 = 2121040049 is a prime.

It is a super-2 number, since 2×21210401132 = 8997622321910105538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2121040092 and 2121040101.

It is not an unprimeable number, because it can be changed into a prime (2121040123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2116306 + ... + 2117307.

It is an arithmetic number, because the mean of its divisors is an integer number (355623576).

Almost surely, 22121040113 is an apocalyptic number.

It is an amenable number.

2121040113 is a deficient number, since it is larger than the sum of its proper divisors (723948495).

2121040113 is a wasteful number, since it uses less digits than its factorization.

2121040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4233783.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 2121040113 is about 46054.7512532638. The cubic root of 2121040113 is about 1284.8417117425.

Adding to 2121040113 its reverse (3110401212), we get a palindrome (5231441325).

The spelling of 2121040113 in words is "two billion, one hundred twenty-one million, forty thousand, one hundred thirteen".

Divisors: 1 3 167 501 4233613 12700839 707013371 2121040113