Base | Representation |
---|---|
bin | 111111001101100… |
… | …1000000011110001 |
3 | 12110211010000001020 |
4 | 1332123020003301 |
5 | 13320441240423 |
6 | 550245130053 |
7 | 103363354263 |
oct | 17633100361 |
9 | 5424100036 |
10 | 2121040113 |
11 | 9992a9915 |
12 | 4b23b9929 |
13 | 27a57682a |
14 | 1619a5b33 |
15 | c63214e3 |
hex | 7e6c80f1 |
2121040113 has 8 divisors (see below), whose sum is σ = 2844988608. Its totient is φ = 1405559184.
The previous prime is 2121040099. The next prime is 2121040123. The reversal of 2121040113 is 3110401212.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2121040113 - 26 = 2121040049 is a prime.
It is a super-2 number, since 2×21210401132 = 8997622321910105538, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2121040092 and 2121040101.
It is not an unprimeable number, because it can be changed into a prime (2121040123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2116306 + ... + 2117307.
It is an arithmetic number, because the mean of its divisors is an integer number (355623576).
Almost surely, 22121040113 is an apocalyptic number.
It is an amenable number.
2121040113 is a deficient number, since it is larger than the sum of its proper divisors (723948495).
2121040113 is a wasteful number, since it uses less digits than its factorization.
2121040113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4233783.
The product of its (nonzero) digits is 48, while the sum is 15.
The square root of 2121040113 is about 46054.7512532638. The cubic root of 2121040113 is about 1284.8417117425.
Adding to 2121040113 its reverse (3110401212), we get a palindrome (5231441325).
The spelling of 2121040113 in words is "two billion, one hundred twenty-one million, forty thousand, one hundred thirteen".
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