Base | Representation |
---|---|
bin | 11110110111011100001… |
… | …000111010010000001001 |
3 | 21111202221221211002022120 |
4 | 132313130020322100021 |
5 | 234223014210401301 |
6 | 4302231523441453 |
7 | 306150065135451 |
oct | 36673410722011 |
9 | 7452857732276 |
10 | 2121112200201 |
11 | 7486165a3425 |
12 | 2a3104226289 |
13 | 125034cb1567 |
14 | 7493b7ccd61 |
15 | 3a295928e36 |
hex | 1eddc23a409 |
2121112200201 has 8 divisors (see below), whose sum is σ = 2828305228224. Its totient is φ = 1413996986160.
The previous prime is 2121112200197. The next prime is 2121112200217. The reversal of 2121112200201 is 1020022111212.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2121112200201 - 22 = 2121112200197 is a prime.
It is a super-3 number, since 3×21211122002013 (a number of 38 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (2121112204201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19389861 + ... + 19498946.
It is an arithmetic number, because the mean of its divisors is an integer number (353538153528).
Almost surely, 22121112200201 is an apocalyptic number.
It is an amenable number.
2121112200201 is a deficient number, since it is larger than the sum of its proper divisors (707193028023).
2121112200201 is a wasteful number, since it uses less digits than its factorization.
2121112200201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38906991.
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 2121112200201 its reverse (1020022111212), we get a palindrome (3141134311413).
The spelling of 2121112200201 in words is "two trillion, one hundred twenty-one billion, one hundred twelve million, two hundred thousand, two hundred one".
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