Base | Representation |
---|---|
bin | 11110110111011100101… |
… | …011010001111111011011 |
3 | 21111202222120202211220002 |
4 | 132313130223101333123 |
5 | 234223024012212311 |
6 | 4302232444523215 |
7 | 306150234543164 |
oct | 36673453217733 |
9 | 7452876684802 |
10 | 2121121210331 |
11 | 748620697912 |
12 | 2a310725050b |
13 | 125036b176b6 |
14 | 7493ca9676b |
15 | 3a29660893b |
hex | 1eddcad1fdb |
2121121210331 has 2 divisors, whose sum is σ = 2121121210332. Its totient is φ = 2121121210330.
The previous prime is 2121121210279. The next prime is 2121121210349. The reversal of 2121121210331 is 1330121211212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2121121210331 is a prime.
It is a super-2 number, since 2×21211212103312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2121121210391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060560605165 + 1060560605166.
It is an arithmetic number, because the mean of its divisors is an integer number (1060560605166).
Almost surely, 22121121210331 is an apocalyptic number.
2121121210331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121121210331 is an equidigital number, since it uses as much as digits as its factorization.
2121121210331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 2121121210331 its reverse (1330121211212), we get a palindrome (3451242421543).
The spelling of 2121121210331 in words is "two trillion, one hundred twenty-one billion, one hundred twenty-one million, two hundred ten thousand, three hundred thirty-one".
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