Base | Representation |
---|---|
bin | 110000001110101001110110… |
… | …011000011101100010110011 |
3 | 1000211000211100110122012200221 |
4 | 300032221312120131202303 |
5 | 210300230404144113321 |
6 | 2031043251103153511 |
7 | 62451450564100411 |
oct | 6016516630354263 |
9 | 1024024313565627 |
10 | 212113241004211 |
11 | 616497a1847738 |
12 | 1b958b732a5897 |
13 | 9148267772b21 |
14 | 3a5449b0062b1 |
15 | 197c8438a4e41 |
hex | c0ea7661d8b3 |
212113241004211 has 2 divisors, whose sum is σ = 212113241004212. Its totient is φ = 212113241004210.
The previous prime is 212113241004157. The next prime is 212113241004251. The reversal of 212113241004211 is 112400142311212.
212113241004211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212113241004211 - 237 = 211975802050739 is a prime.
It is not a weakly prime, because it can be changed into another prime (212113241004251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106056620502105 + 106056620502106.
It is an arithmetic number, because the mean of its divisors is an integer number (106056620502106).
Almost surely, 2212113241004211 is an apocalyptic number.
212113241004211 is a deficient number, since it is larger than the sum of its proper divisors (1).
212113241004211 is an equidigital number, since it uses as much as digits as its factorization.
212113241004211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 212113241004211 its reverse (112400142311212), we get a palindrome (324513383315423).
The spelling of 212113241004211 in words is "two hundred twelve trillion, one hundred thirteen billion, two hundred forty-one million, four thousand, two hundred eleven".
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