Base | Representation |
---|---|
bin | 110000001110110000010101… |
… | …110001111010110000100001 |
3 | 1000211001111100011110011101111 |
4 | 300032300111301322300201 |
5 | 210300334142304101423 |
6 | 2031050402421503321 |
7 | 62452115360343064 |
oct | 6016602561726041 |
9 | 1024044304404344 |
10 | 212120210222113 |
11 | 61651748787256 |
12 | 1b95a399271b41 |
13 | 9148b0858babb |
14 | 3a5495c82c8db |
15 | 197cb0063d60d |
hex | c0ec15c7ac21 |
212120210222113 has 2 divisors, whose sum is σ = 212120210222114. Its totient is φ = 212120210222112.
The previous prime is 212120210222051. The next prime is 212120210222153. The reversal of 212120210222113 is 311222012021212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 199037723773329 + 13082486448784 = 14108073^2 + 3616972^2 .
It is a cyclic number.
It is not a de Polignac number, because 212120210222113 - 213 = 212120210213921 is a prime.
It is not a weakly prime, because it can be changed into another prime (212120210222153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106060105111056 + 106060105111057.
It is an arithmetic number, because the mean of its divisors is an integer number (106060105111057).
Almost surely, 2212120210222113 is an apocalyptic number.
It is an amenable number.
212120210222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
212120210222113 is an equidigital number, since it uses as much as digits as its factorization.
212120210222113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 212120210222113 its reverse (311222012021212), we get a palindrome (523342222243325).
The spelling of 212120210222113 in words is "two hundred twelve trillion, one hundred twenty billion, two hundred ten million, two hundred twenty-two thousand, one hundred thirteen".
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