Base | Representation |
---|---|
bin | 110000001110110001001010… |
… | …110111111101110110111010 |
3 | 1000211001120122020121101002121 |
4 | 300032301022313331312322 |
5 | 210300343003324000442 |
6 | 2031051031042151454 |
7 | 62452146425002366 |
oct | 6016611267756672 |
9 | 1024046566541077 |
10 | 212121101000122 |
11 | 6165206558aa26 |
12 | 1b95a5a765258a |
13 | 9148c1aca6a92 |
14 | 3a54a04c682a6 |
15 | 197cb53947967 |
hex | c0ec4adfddba |
212121101000122 has 4 divisors (see below), whose sum is σ = 318181651500186. Its totient is φ = 106060550500060.
The previous prime is 212121101000117. The next prime is 212121101000153. The reversal of 212121101000122 is 221000101121212.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 206981136411921 + 5139964588201 = 14386839^2 + 2267149^2 .
It is a super-3 number, since 3×2121211010001223 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 212121101000096 and 212121101000105.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53030275250029 + ... + 53030275250032.
Almost surely, 2212121101000122 is an apocalyptic number.
212121101000122 is a deficient number, since it is larger than the sum of its proper divisors (106060550500064).
212121101000122 is a wasteful number, since it uses less digits than its factorization.
212121101000122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 106060550500063.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 212121101000122 its reverse (221000101121212), we get a palindrome (433121202121334).
The spelling of 212121101000122 in words is "two hundred twelve trillion, one hundred twenty-one billion, one hundred one million, one hundred twenty-two", and thus it is an aban number.
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