Base | Representation |
---|---|
bin | 11110110111100010000… |
… | …110011000100010100011 |
3 | 21111210012220222122210102 |
4 | 132313202012120202203 |
5 | 234223220310413443 |
6 | 4302245455053015 |
7 | 306152421133361 |
oct | 36674206304243 |
9 | 7453186878712 |
10 | 2121212201123 |
11 | 748667a95614 |
12 | 2a313181116b |
13 | 12504c9255c2 |
14 | 7494abc0631 |
15 | 3a29e5cdcb8 |
hex | 1ede21988a3 |
2121212201123 has 2 divisors, whose sum is σ = 2121212201124. Its totient is φ = 2121212201122.
The previous prime is 2121212201047. The next prime is 2121212201161. The reversal of 2121212201123 is 3211022121212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2121212201123 - 226 = 2121145092259 is a prime.
It is a super-3 number, since 3×21212122011233 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 2121212201095 and 2121212201104.
It is not a weakly prime, because it can be changed into another prime (2121212221123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060606100561 + 1060606100562.
It is an arithmetic number, because the mean of its divisors is an integer number (1060606100562).
Almost surely, 22121212201123 is an apocalyptic number.
2121212201123 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121212201123 is an equidigital number, since it uses as much as digits as its factorization.
2121212201123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 2121212201123 its reverse (3211022121212), we get a palindrome (5332234322335).
The spelling of 2121212201123 in words is "two trillion, one hundred twenty-one billion, two hundred twelve million, two hundred one thousand, one hundred twenty-three".
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