Base | Representation |
---|---|
bin | 1100010110001101110… |
… | …1101001010001101011 |
3 | 202021112011011211120102 |
4 | 3011203131221101223 |
5 | 11433411230110011 |
6 | 241240401020015 |
7 | 21216404132465 |
oct | 3054335512153 |
9 | 667464154512 |
10 | 212122113131 |
11 | 81a62448215 |
12 | 3513b32460b |
13 | 1700686a696 |
14 | a3a4009135 |
15 | 57b77b673b |
hex | 316376946b |
212122113131 has 2 divisors, whose sum is σ = 212122113132. Its totient is φ = 212122113130.
The previous prime is 212122113097. The next prime is 212122113139. The reversal of 212122113131 is 131311221212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212122113131 - 230 = 211048371307 is a prime.
It is a super-2 number, since 2×2121221131312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (212122113139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106061056565 + 106061056566.
It is an arithmetic number, because the mean of its divisors is an integer number (106061056566).
Almost surely, 2212122113131 is an apocalyptic number.
212122113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
212122113131 is an equidigital number, since it uses as much as digits as its factorization.
212122113131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 144, while the sum is 20.
Adding to 212122113131 its reverse (131311221212), we get a palindrome (343433334343).
The spelling of 212122113131 in words is "two hundred twelve billion, one hundred twenty-two million, one hundred thirteen thousand, one hundred thirty-one".
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