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2121300113 = 5633767851
BaseRepresentation
bin111111001110000…
…0111100010010001
312110211121012200212
41332130013202101
513321023100423
6550254453505
7103365516302
oct17634074221
95424535625
102121300113
11999467199
124b2504295
1327a637c8a
14161a327a9
15c6373578
hex7e707891

2121300113 has 4 divisors (see below), whose sum is σ = 2125068528. Its totient is φ = 2117531700.

The previous prime is 2121300089. The next prime is 2121300119. The reversal of 2121300113 is 3110031212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2121300113 - 214 = 2121283729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2121300119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1883363 + ... + 1884488.

It is an arithmetic number, because the mean of its divisors is an integer number (531267132).

Almost surely, 22121300113 is an apocalyptic number.

It is an amenable number.

2121300113 is a deficient number, since it is larger than the sum of its proper divisors (3768415).

2121300113 is an equidigital number, since it uses as much as digits as its factorization.

2121300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3768414.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 2121300113 is about 46057.5738939862. The cubic root of 2121300113 is about 1284.8942088161.

Adding to 2121300113 its reverse (3110031212), we get a palindrome (5231331325).

The spelling of 2121300113 in words is "two billion, one hundred twenty-one million, three hundred thousand, one hundred thirteen".

Divisors: 1 563 3767851 2121300113