Base | Representation |
---|---|
bin | 11110110111101000100… |
… | …010011111010001100001 |
3 | 21111210111110021012100020 |
4 | 132313220202133101201 |
5 | 234223430434411113 |
6 | 4302304314344053 |
7 | 306155202314322 |
oct | 36675042372141 |
9 | 7453443235306 |
10 | 2121320232033 |
11 | 748712a71862 |
12 | 2a3161a2b029 |
13 | 12506911b612 |
14 | 7495b2a2449 |
15 | 3a2a8d1d023 |
hex | 1ede889f461 |
2121320232033 has 4 divisors (see below), whose sum is σ = 2828426976048. Its totient is φ = 1414213488020.
The previous prime is 2121320232011. The next prime is 2121320232047. The reversal of 2121320232033 is 3302320231212.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2121320232033 - 25 = 2121320232001 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2121320231994 and 2121320232012.
It is not an unprimeable number, because it can be changed into a prime (2121320232133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353553372003 + ... + 353553372008.
It is an arithmetic number, because the mean of its divisors is an integer number (707106744012).
Almost surely, 22121320232033 is an apocalyptic number.
It is an amenable number.
2121320232033 is a deficient number, since it is larger than the sum of its proper divisors (707106744015).
2121320232033 is an equidigital number, since it uses as much as digits as its factorization.
2121320232033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 707106744014.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 2121320232033 its reverse (3302320231212), we get a palindrome (5423640463245).
The spelling of 2121320232033 in words is "two trillion, one hundred twenty-one billion, three hundred twenty million, two hundred thirty-two thousand, thirty-three".
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