Base | Representation |
---|---|
bin | 1001101001011001000101… |
… | …11111011110011101111001 |
3 | 2210002222120110002202011021 |
4 | 10310230202333132131321 |
5 | 10240030101204241103 |
6 | 113041152045502441 |
7 | 4316422404312445 |
oct | 464544277363571 |
9 | 83088513082137 |
10 | 21213430540153 |
11 | 6839624563795 |
12 | 246737ab71a21 |
13 | bab558215807 |
14 | 534a42385825 |
15 | 26bc23bbabbd |
hex | 134b22fde779 |
21213430540153 has 4 divisors (see below), whose sum is σ = 21213445535568. Its totient is φ = 21213415544740.
The previous prime is 21213430540111. The next prime is 21213430540229. The reversal of 21213430540153 is 35104503431212.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 21213430540153 - 237 = 21075991586681 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21213430540553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5125543 + ... + 8288428.
It is an arithmetic number, because the mean of its divisors is an integer number (5303361383892).
Almost surely, 221213430540153 is an apocalyptic number.
It is an amenable number.
21213430540153 is a deficient number, since it is larger than the sum of its proper divisors (14995415).
21213430540153 is a wasteful number, since it uses less digits than its factorization.
21213430540153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14995414.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 21213430540153 its reverse (35104503431212), we get a palindrome (56317933971365).
The spelling of 21213430540153 in words is "twenty-one trillion, two hundred thirteen billion, four hundred thirty million, five hundred forty thousand, one hundred fifty-three".
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