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21216015265433 is a prime number
BaseRepresentation
bin1001101001011101111010…
…00011011010111010011001
32210010020020120201101200012
410310232331003122322121
510240100344401443213
6113042300341251305
74316543431154612
oct464567503327231
983106216641605
1021216015265433
11683a73057608a
122467980703b35
13bab87a86b061
14534c0976cc09
1526bd25a804a8
hex134bbd0dae99

21216015265433 has 2 divisors, whose sum is σ = 21216015265434. Its totient is φ = 21216015265432.

The previous prime is 21216015265369. The next prime is 21216015265451. The reversal of 21216015265433 is 33456251061212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13952974095424 + 7263041170009 = 3735368^2 + 2695003^2 .

It is a cyclic number.

It is not a de Polignac number, because 21216015265433 - 26 = 21216015265369 is a prime.

It is not a weakly prime, because it can be changed into another prime (21216015265453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10608007632716 + 10608007632717.

It is an arithmetic number, because the mean of its divisors is an integer number (10608007632717).

Almost surely, 221216015265433 is an apocalyptic number.

It is an amenable number.

21216015265433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21216015265433 is an equidigital number, since it uses as much as digits as its factorization.

21216015265433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 41.

The spelling of 21216015265433 in words is "twenty-one trillion, two hundred sixteen billion, fifteen million, two hundred sixty-five thousand, four hundred thirty-three".