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2122020010113 = 32924391034599
BaseRepresentation
bin11110111000010010001…
…111111011100010000001
321111212022020000121101220
4132320102033323202001
5234231344110310423
64302501553145253
7306211430322543
oct36702217734201
97455266017356
102122020010113
11748a41a7a453
122a331825b229
1312514b0b09a3
14749c61bd693
153a2ea4999e3
hex1ee123fb881

2122020010113 has 8 divisors (see below), whose sum is σ = 2926924152000. Its totient is φ = 1365897937488.

The previous prime is 2122020010093. The next prime is 2122020010127. The reversal of 2122020010113 is 3110100202212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2122020010113 - 25 = 2122020010081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2122020010092 and 2122020010101.

It is not an unprimeable number, because it can be changed into a prime (2122020110113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12195517213 + ... + 12195517386.

It is an arithmetic number, because the mean of its divisors is an integer number (365865519000).

Almost surely, 22122020010113 is an apocalyptic number.

It is an amenable number.

2122020010113 is a deficient number, since it is larger than the sum of its proper divisors (804904141887).

2122020010113 is a wasteful number, since it uses less digits than its factorization.

2122020010113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24391034631.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 2122020010113 its reverse (3110100202212), we get a palindrome (5232120212325).

The spelling of 2122020010113 in words is "two trillion, one hundred twenty-two billion, twenty million, ten thousand, one hundred thirteen".

Divisors: 1 3 29 87 24391034599 73173103797 707340003371 2122020010113