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21221533520153 = 125116116961473
BaseRepresentation
bin1001101001101000001011…
…11101111001000100011001
32210010202111011021210001122
410310310011331321010121
510240143200040121103
6113045012104455025
74320130245436031
oct464640575710431
983122434253048
1021221533520153
11684200247857a
122468a6077a475
13bac249ba3935
145351b05b88c1
1526c04a258b38
hex134d05f79119

21221533520153 has 4 divisors (see below), whose sum is σ = 21221551732788. Its totient is φ = 21221515307520.

The previous prime is 21221533520147. The next prime is 21221533520171. The reversal of 21221533520153 is 35102533512212.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6313224087769 + 14908309432384 = 2512613^2 + 3861128^2 .

It is a cyclic number.

It is not a de Polignac number, because 21221533520153 - 214 = 21221533503769 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21221533520183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7229576 + ... + 9731897.

It is an arithmetic number, because the mean of its divisors is an integer number (5305387933197).

Almost surely, 221221533520153 is an apocalyptic number.

It is an amenable number.

21221533520153 is a deficient number, since it is larger than the sum of its proper divisors (18212635).

21221533520153 is a wasteful number, since it uses less digits than its factorization.

21221533520153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18212634.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 21221533520153 in words is "twenty-one trillion, two hundred twenty-one billion, five hundred thirty-three million, five hundred twenty thousand, one hundred fifty-three".

Divisors: 1 1251161 16961473 21221533520153