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212222142543457 is a prime number
BaseRepresentation
bin110000010000001111010001…
…011010110111011001100001
31000211102020110000002121012101
4300100033101122313121201
5210304021421442342312
62031205301213130401
762462354346645364
oct6020172132673141
91024366400077171
10212222142543457
11616909a5933a42
121b9760a6189a01
13915560150a847
143a5986c36c0db
1519805b931ca57
hexc103d16b7661

212222142543457 has 2 divisors, whose sum is σ = 212222142543458. Its totient is φ = 212222142543456.

The previous prime is 212222142543373. The next prime is 212222142543479. The reversal of 212222142543457 is 754345241222212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 172852654254336 + 39369488289121 = 13147344^2 + 6274511^2 .

It is a cyclic number.

It is not a de Polignac number, because 212222142543457 - 27 = 212222142543329 is a prime.

It is a super-3 number, since 3×2122221425434573 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (212222142543157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106111071271728 + 106111071271729.

It is an arithmetic number, because the mean of its divisors is an integer number (106111071271729).

Almost surely, 2212222142543457 is an apocalyptic number.

It is an amenable number.

212222142543457 is a deficient number, since it is larger than the sum of its proper divisors (1).

212222142543457 is an equidigital number, since it uses as much as digits as its factorization.

212222142543457 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2150400, while the sum is 46.

Adding to 212222142543457 its reverse (754345241222212), we get a palindrome (966567383765669).

The spelling of 212222142543457 in words is "two hundred twelve trillion, two hundred twenty-two billion, one hundred forty-two million, five hundred forty-three thousand, four hundred fifty-seven".