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212222441113 = 1123188978131
BaseRepresentation
bin1100010110100101110…
…0010111011010011001
3202021210010222000200121
43011221130113122121
511434112421103423
6241254343233241
721222032662054
oct3055134273231
9667703860617
10212222441113
1182004043101
1235168a48821
1317021597557
14a3b3483a9b
1557c14d345d
hex3169717699

212222441113 has 4 divisors (see below), whose sum is σ = 212411420368. Its totient is φ = 212033461860.

The previous prime is 212222441083. The next prime is 212222441117. The reversal of 212222441113 is 311144222212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 212222441113 - 221 = 212220343961 is a prime.

It is a super-3 number, since 3×2122224411133 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (212222441117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94487943 + ... + 94490188.

It is an arithmetic number, because the mean of its divisors is an integer number (53102855092).

Almost surely, 2212222441113 is an apocalyptic number.

It is an amenable number.

212222441113 is a deficient number, since it is larger than the sum of its proper divisors (188979255).

212222441113 is a wasteful number, since it uses less digits than its factorization.

212222441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188979254.

The product of its digits is 1536, while the sum is 25.

Adding to 212222441113 its reverse (311144222212), we get a palindrome (523366663325).

The spelling of 212222441113 in words is "two hundred twelve billion, two hundred twenty-two million, four hundred forty-one thousand, one hundred thirteen".

Divisors: 1 1123 188978131 212222441113