Base | Representation |
---|---|
bin | 11110111000100101011… |
… | …010000110011101001011 |
3 | 21111220010121212002222120 |
4 | 132320211122012131023 |
5 | 234233023402142103 |
6 | 4302553514422323 |
7 | 306222412421046 |
oct | 36704532063513 |
9 | 7456117762876 |
10 | 2122341443403 |
11 | 749097462aa5 |
12 | 2a33a7a319a3 |
13 | 12519c8743bc |
14 | 74a16b71c5d |
15 | 3a3187de253 |
hex | 1ee2568674b |
2122341443403 has 4 divisors (see below), whose sum is σ = 2829788591208. Its totient is φ = 1414894295600.
The previous prime is 2122341443399. The next prime is 2122341443441. The reversal of 2122341443403 is 3043441432212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2122341443403 - 22 = 2122341443399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2122341443473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353723573898 + ... + 353723573903.
It is an arithmetic number, because the mean of its divisors is an integer number (707447147802).
Almost surely, 22122341443403 is an apocalyptic number.
2122341443403 is a deficient number, since it is larger than the sum of its proper divisors (707447147805).
2122341443403 is an equidigital number, since it uses as much as digits as its factorization.
2122341443403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 707447147804.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 2122341443403 its reverse (3043441432212), we get a palindrome (5165782875615).
The spelling of 2122341443403 in words is "two trillion, one hundred twenty-two billion, three hundred forty-one million, four hundred forty-three thousand, four hundred three".
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