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2122414113130 = 25331641212723
BaseRepresentation
bin11110111000101001101…
…111010100000101101010
321111220022200121010002221
4132320221233110011222
5234233201003110010
64303005032144254
7306224254204123
oct36705157240552
97456280533087
102122414113130
11749124487923
122a340823808a
131251b193913c
1474a2268b04a
153a31ed95dda
hex1ee29bd416a

2122414113130 has 16 divisors (see below), whose sum is σ = 3831887238624. Its totient is φ = 846400793040.

The previous prime is 2122414113103. The next prime is 2122414113139. The reversal of 2122414113130 is 313114142212.

It is a super-2 number, since 2×21224141131302 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2122414113095 and 2122414113104.

It is not an unprimeable number, because it can be changed into a prime (2122414113139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 320603052 + ... + 320609671.

It is an arithmetic number, because the mean of its divisors is an integer number (239492952414).

Almost surely, 22122414113130 is an apocalyptic number.

2122414113130 is a deficient number, since it is larger than the sum of its proper divisors (1709473125494).

2122414113130 is a wasteful number, since it uses less digits than its factorization.

2122414113130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 641213061.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2122414113130 its reverse (313114142212), we get a palindrome (2435528255342).

The spelling of 2122414113130 in words is "two trillion, one hundred twenty-two billion, four hundred fourteen million, one hundred thirteen thousand, one hundred thirty".

Divisors: 1 2 5 10 331 662 1655 3310 641212723 1282425446 3206063615 6412127230 212241411313 424482822626 1061207056565 2122414113130