Base | Representation |
---|---|
bin | 11110111001001100111… |
… | …001100101111101001001 |
3 | 21111221211210120222220202 |
4 | 132321030321211331021 |
5 | 234240403011312223 |
6 | 4303143343501545 |
7 | 306245006225024 |
oct | 36711471457511 |
9 | 7457753528822 |
10 | 2123004010313 |
11 | 7493a746535a |
12 | 2a35518b78b5 |
13 | 125276c08424 |
14 | 74a7ab641bb |
15 | 3a356a6a428 |
hex | 1ee4ce65f49 |
2123004010313 has 2 divisors, whose sum is σ = 2123004010314. Its totient is φ = 2123004010312.
The previous prime is 2123004010223. The next prime is 2123004010319. The reversal of 2123004010313 is 3130104003212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2123003444809 + 565504 = 1457053^2 + 752^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2123004010313 is a prime.
It is a super-2 number, since 2×21230040103132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2123004010319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061502005156 + 1061502005157.
It is an arithmetic number, because the mean of its divisors is an integer number (1061502005157).
Almost surely, 22123004010313 is an apocalyptic number.
It is an amenable number.
2123004010313 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123004010313 is an equidigital number, since it uses as much as digits as its factorization.
2123004010313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 2123004010313 its reverse (3130104003212), we get a palindrome (5253108013525).
The spelling of 2123004010313 in words is "two trillion, one hundred twenty-three billion, four million, ten thousand, three hundred thirteen".
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