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2123013433 is a prime number
BaseRepresentation
bin111111010001010…
…1001110100111001
312110221211020221011
41332202221310321
513321442412213
6550355313521
7103416213352
oct17642516471
95427736834
102123013433
1199a427462
124b2bab8a1
1327aab7a88
14161d5ad29
15c65b103d
hex7e8a9d39

2123013433 has 2 divisors, whose sum is σ = 2123013434. Its totient is φ = 2123013432.

The previous prime is 2123013401. The next prime is 2123013437. The reversal of 2123013433 is 3343103212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1842383929 + 280629504 = 42923^2 + 16752^2 .

It is a cyclic number.

It is not a de Polignac number, because 2123013433 - 25 = 2123013401 is a prime.

It is not a weakly prime, because it can be changed into another prime (2123013437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061506716 + 1061506717.

It is an arithmetic number, because the mean of its divisors is an integer number (1061506717).

Almost surely, 22123013433 is an apocalyptic number.

It is an amenable number.

2123013433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2123013433 is an equidigital number, since it uses as much as digits as its factorization.

2123013433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 22.

The square root of 2123013433 is about 46076.1699037583. The cubic root of 2123013433 is about 1285.2400411537.

Adding to 2123013433 its reverse (3343103212), we get a palindrome (5466116645).

The spelling of 2123013433 in words is "two billion, one hundred twenty-three million, thirteen thousand, four hundred thirty-three".