Base | Representation |
---|---|
bin | 10011110001011110… |
… | …111111001100101001 |
3 | 2000210122102212020221 |
4 | 103301132333030221 |
5 | 321440203121132 |
6 | 13430432250041 |
7 | 1351063040644 |
oct | 236136771451 |
9 | 60718385227 |
10 | 21231301417 |
11 | 9005574aa7 |
12 | 41463a0921 |
13 | 200480b561 |
14 | 1055a42a5b |
15 | 843ddae97 |
hex | 4f17bf329 |
21231301417 has 2 divisors, whose sum is σ = 21231301418. Its totient is φ = 21231301416.
The previous prime is 21231301397. The next prime is 21231301501. The reversal of 21231301417 is 71410313212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19139062336 + 2092239081 = 138344^2 + 45741^2 .
It is a cyclic number.
It is not a de Polignac number, because 21231301417 - 231 = 19083817769 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21231301391 and 21231301400.
It is not a weakly prime, because it can be changed into another prime (21231701417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10615650708 + 10615650709.
It is an arithmetic number, because the mean of its divisors is an integer number (10615650709).
Almost surely, 221231301417 is an apocalyptic number.
It is an amenable number.
21231301417 is a deficient number, since it is larger than the sum of its proper divisors (1).
21231301417 is an equidigital number, since it uses as much as digits as its factorization.
21231301417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 21231301417 its reverse (71410313212), we get a palindrome (92641614629).
The spelling of 21231301417 in words is "twenty-one billion, two hundred thirty-one million, three hundred one thousand, four hundred seventeen".
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