Base | Representation |
---|---|
bin | 11110111001011110101… |
… | …110001010010000001011 |
3 | 21111222121122012101222102 |
4 | 132321132232022100023 |
5 | 234242011032100042 |
6 | 4303233144144015 |
7 | 306255266511164 |
oct | 36713656122013 |
9 | 7458548171872 |
10 | 2123303003147 |
11 | 749540211077 |
12 | 2a3615a6800b |
13 | 1252c3b42971 |
14 | 74aa875476b |
15 | 3a372e2ab32 |
hex | 1ee5eb8a40b |
2123303003147 has 2 divisors, whose sum is σ = 2123303003148. Its totient is φ = 2123303003146.
The previous prime is 2123303003077. The next prime is 2123303003201. The reversal of 2123303003147 is 7413003033212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2123303003147 - 218 = 2123302741003 is a prime.
It is a super-3 number, since 3×21233030031473 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2123303033147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061651501573 + 1061651501574.
It is an arithmetic number, because the mean of its divisors is an integer number (1061651501574).
Almost surely, 22123303003147 is an apocalyptic number.
2123303003147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123303003147 is an equidigital number, since it uses as much as digits as its factorization.
2123303003147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 29.
Adding to 2123303003147 its reverse (7413003033212), we get a palindrome (9536306036359).
The spelling of 2123303003147 in words is "two trillion, one hundred twenty-three billion, three hundred three million, three thousand, one hundred forty-seven".
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