Base | Representation |
---|---|
bin | 1001101001111101111111… |
… | …11110111111010001100011 |
3 | 2210011212201022012021002121 |
4 | 10310332333332333101203 |
5 | 10240341141020220413 |
6 | 113054230123325111 |
7 | 4321023405450301 |
oct | 464767776772143 |
9 | 83155638167077 |
10 | 21233244304483 |
11 | 6846a71951132 |
12 | 246b18a680797 |
13 | bb0395145213 |
14 | 5359a1a2d271 |
15 | 26c4d33eab8d |
hex | 134fbffbf463 |
21233244304483 has 2 divisors, whose sum is σ = 21233244304484. Its totient is φ = 21233244304482.
The previous prime is 21233244304451. The next prime is 21233244304487. The reversal of 21233244304483 is 38440344233212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21233244304483 - 25 = 21233244304451 is a prime.
It is not a weakly prime, because it can be changed into another prime (21233244304487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10616622152241 + 10616622152242.
It is an arithmetic number, because the mean of its divisors is an integer number (10616622152242).
Almost surely, 221233244304483 is an apocalyptic number.
21233244304483 is a deficient number, since it is larger than the sum of its proper divisors (1).
21233244304483 is an equidigital number, since it uses as much as digits as its factorization.
21233244304483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1327104, while the sum is 43.
Adding to 21233244304483 its reverse (38440344233212), we get a palindrome (59673588537695).
The spelling of 21233244304483 in words is "twenty-one trillion, two hundred thirty-three billion, two hundred forty-four million, three hundred four thousand, four hundred eighty-three".
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