Base | Representation |
---|---|
bin | 110000010001110110100010… |
… | …110101011001101010110001 |
3 | 1000211210211122221122010211221 |
4 | 300101312202311121222301 |
5 | 210312331021202320423 |
6 | 2031332240350505041 |
7 | 62503361266543030 |
oct | 6021664265315261 |
9 | 1024724587563757 |
10 | 212333030120113 |
11 | 61723a28aa0581 |
12 | 1b993692205181 |
13 | 9162bc3871526 |
14 | 3a60d8b396717 |
15 | 19834092dae5d |
hex | c11da2d59ab1 |
212333030120113 has 32 divisors (see below), whose sum is σ = 246789443520000. Its totient is φ = 178924406685696.
The previous prime is 212333030120047. The next prime is 212333030120129. The reversal of 212333030120113 is 311021030333212.
It is not a de Polignac number, because 212333030120113 - 225 = 212332996565681 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (212333030120153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 225067813 + ... + 226009261.
It is an arithmetic number, because the mean of its divisors is an integer number (7712170110000).
Almost surely, 2212333030120113 is an apocalyptic number.
It is an amenable number.
212333030120113 is a deficient number, since it is larger than the sum of its proper divisors (34456413399887).
212333030120113 is an equidigital number, since it uses as much as digits as its factorization.
212333030120113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 942961.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 212333030120113 its reverse (311021030333212), we get a palindrome (523354060453325).
The spelling of 212333030120113 in words is "two hundred twelve trillion, three hundred thirty-three billion, thirty million, one hundred twenty thousand, one hundred thirteen".
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