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2124002710433 is a prime number
BaseRepresentation
bin11110111010001000011…
…011010101001110100001
321112001102101211012221002
4132322020123111032201
5234244424143213213
64303430421241345
7306311524103132
oct36721033251641
97461371735832
102124002710433
1174986a18055a
122a3790263255
131253a5aaba46
1474b33653c89
153a3b4591658
hex1ee886d53a1

2124002710433 has 2 divisors, whose sum is σ = 2124002710434. Its totient is φ = 2124002710432.

The previous prime is 2124002710429. The next prime is 2124002710471. The reversal of 2124002710433 is 3340172004212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2001059209744 + 122943500689 = 1414588^2 + 350633^2 .

It is a cyclic number.

It is not a de Polignac number, because 2124002710433 - 22 = 2124002710429 is a prime.

It is a super-2 number, since 2×21240027104332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2124002710396 and 2124002710405.

It is not a weakly prime, because it can be changed into another prime (2124002710483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062001355216 + 1062001355217.

It is an arithmetic number, because the mean of its divisors is an integer number (1062001355217).

Almost surely, 22124002710433 is an apocalyptic number.

It is an amenable number.

2124002710433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2124002710433 is an equidigital number, since it uses as much as digits as its factorization.

2124002710433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 29.

Adding to 2124002710433 its reverse (3340172004212), we get a palindrome (5464174714645).

The spelling of 2124002710433 in words is "two trillion, one hundred twenty-four billion, two million, seven hundred ten thousand, four hundred thirty-three".