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21240442324433 is a prime number
BaseRepresentation
bin1001101010001011011010…
…00001010000010111010001
32210012120021221112120012002
410311011231001100113101
510241000411213340213
6113101420254043345
74321366650556223
oct465055501202721
983176257476162
1021240442324433
11684a025a56052
1224706591a9555
13bb0c71491117
145360859b4413
1526c7a52cc658
hex13516d0505d1

21240442324433 has 2 divisors, whose sum is σ = 21240442324434. Its totient is φ = 21240442324432.

The previous prime is 21240442324403. The next prime is 21240442324457. The reversal of 21240442324433 is 33442324404212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18878955480064 + 2361486844369 = 4344992^2 + 1536713^2 .

It is a cyclic number.

It is not a de Polignac number, because 21240442324433 - 212 = 21240442320337 is a prime.

It is not a weakly prime, because it can be changed into another prime (21240442324403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10620221162216 + 10620221162217.

It is an arithmetic number, because the mean of its divisors is an integer number (10620221162217).

Almost surely, 221240442324433 is an apocalyptic number.

It is an amenable number.

21240442324433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21240442324433 is an equidigital number, since it uses as much as digits as its factorization.

21240442324433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 442368, while the sum is 38.

Adding to 21240442324433 its reverse (33442324404212), we get a palindrome (54682766728645).

The spelling of 21240442324433 in words is "twenty-one trillion, two hundred forty billion, four hundred forty-two million, three hundred twenty-four thousand, four hundred thirty-three".