Base | Representation |
---|---|
bin | 110000010010111101000111… |
… | …011000100111111111111011 |
3 | 1000212002002020211221011002211 |
4 | 300102331013120213333323 |
5 | 210320101213121330212 |
6 | 2031431131423035551 |
7 | 62512013130610024 |
oct | 6022750730477773 |
9 | 1025062224834084 |
10 | 212408805261307 |
11 | 617530830a1706 |
12 | 1b9a62bb13bbb7 |
13 | 916a0ab605795 |
14 | 3a648d8da7c4b |
15 | 19853919199a7 |
hex | c12f47627ffb |
212408805261307 has 2 divisors, whose sum is σ = 212408805261308. Its totient is φ = 212408805261306.
The previous prime is 212408805261299. The next prime is 212408805261371. The reversal of 212408805261307 is 703162508804212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212408805261307 - 23 = 212408805261299 is a prime.
It is not a weakly prime, because it can be changed into another prime (212408805261007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106204402630653 + 106204402630654.
It is an arithmetic number, because the mean of its divisors is an integer number (106204402630654).
Almost surely, 2212408805261307 is an apocalyptic number.
212408805261307 is a deficient number, since it is larger than the sum of its proper divisors (1).
212408805261307 is an equidigital number, since it uses as much as digits as its factorization.
212408805261307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1290240, while the sum is 49.
The spelling of 212408805261307 in words is "two hundred twelve trillion, four hundred eight billion, eight hundred five million, two hundred sixty-one thousand, three hundred seven".
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